Physics Electrostatics Potential & Capacitance JEE Main 2022 - ( Capacitance ) MCQ (Single Correct)

A source of potential difference V is connected to the combination of two identical capacitors as shown in the figure. When key 'K' is closed, the total energy stored across the combination is E 1 . Now key 'K' is opened and dielectric of dielectric constant 5 is introduced between the plates of the capacitors. The total energy stored across the combination is now E 2 . The ratio E 1 /E 2 will be:

A
B
C
D

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The correct answer is:
C

(i) Switch is closed

C eq = 2C

Energy

(ii) When switch is opened charge on right capacitor remain CV while potential on left capacitor remain same

Dielectric K = 5

C ’ = KC

C ’ =5C

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